Converting base-10 to base2 in Ruby using recursion (Binary converter) -

i convert base10 number base2 in ruby without using built in to_s(2) method, using recursion.

i wrote this:

def to_binary(d)     if d<1        return ""   else     return to_binary(d/2).to_s + (d%2).to_s   end end 

this return correct results except 0. there way return 0 0 without having leading zeroes numbers greater 0?

you can modify checks bit:

def to_binary(d)     return d.to_s if [0,1].include?(d) # same "if d == 0 || d == 1"   to_binary(d/2) + (d%2).to_s end  to_binary(10) == "1010" #=> true to_binary(0) == "0" #=> true 

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you write above method as:

def to_binary(d)     return d.to_s if [0,1].include?(d)    div,mod = d.divmod(2)   to_binary(div) + mod.to_s end