regex - Python re.findall getting value -


i have text file have multi lines in same following pattern

server:x.x.x # u:100 # p:100 # pre:00 # tel:xxxxxx

i built code value after pre:

x2 = (re.findall(r'pre:(\d+)',s))

i'm not familiar re patterns , code don't value if + or empty value ( none value )

any suggestions generlize code ever value after pre: until next # without space ?

how pattern? until next " #" without being greedy (that's ? for).

r"pre:(.*?) #"

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