java - RecyclerView: IndexOutOfBoundsException. Invalid item position -

i have 2 fragments: a & b.

fragment b contains searchview , recyclerview.

adapter = new searchlistadapter(items);  recyclerview = new recyclerview(getcontext()); recyclerview.sethasfixedsize(true); recyclerview.setadapter(adapter); recyclerview.setlayoutmanager(new linearlayoutmanager(getcontext()));  params = new relativelayout.layoutparams(layoutparams.match_parent, layoutparams.match_parent); params.addrule(below, search_view_id); addview(recyclerview, params);  @override public boolean onquerytextchange(string newtext) {     arraylist<mymodel> filteredmodellist = adapter.filter(newtext);     recyclerview.scrolltoposition(0);      return true; } 

implementing filtering taken away: how filter recyclerview searchview

problem

1) @ beginning on fragment a, go fragment b administered in searchview more characters , filtered list (for example consisting of single element).

2) next, through getfragmentmanager().popbackstack(); return fragment a.

3) @ same time, in fragment b in method of onstop(); clean searchview:

@override public void onstop() {     if(searchview != null)     {         searchview.setquery("", false);     } } 

4) next, return fragment b , error:

java.lang.indexoutofboundsexception: inconsistency detected. invalid item position 1(offset:35).state:35

i've been looking @ problem , found following:

a) issue 77846

b) issue 77232

c) habra

d) recyclerview layoutmanager part 1 (generatedefaultlayoutparams)

e) indexoutofboundsexception invalid item position xx(xx). item count:xx

he came conclusion bug recyclerview , has not yet been fixed.

as result, necessary implement filtering without animation:

public void filter(string chartext) {     chartext = chartext.tolowercase();     mitems = new arraylist<mymodel>();     if (chartext.length() == 0)     {         mitems.addall(moriginalitems);     }     else     {         (mymodel model : moriginalitems)         {             string textid = model.getid().tolowercase();             if (textid.contains(chartext))             {                 mitems.add(model);             }         }     }      notifydatasetchanged(); } 

is true, , there error in code?

thank you!

update

activity:

public class myactivity extends appcompatactivity 

simplefragmentmanager:

private static void moveto(basefragment fragment) {     if(fragment != null)     {         fragmentmanager fragmentmanager = _activity.getfragmentmanager();         fragmenttransaction ft = fragmentmanager.begintransaction();         basefragment currentfragment = getcurrentfragment();          if(fragment != currentfragment)         {             ft.replace(_containerid, fragment, fragment.gettype());             if (currentfragment != null) ft.addtobackstack(null);             ft.commit();         }     } } 

fragment & b:

@nullable @override public view oncreateview(layoutinflater inflater, viewgroup container, bundle savedinstancestate) {     if(view == null)     {         view = new alayout(container.getcontext());         //if fragment b > view = new blayout(container.getcontext());         view.setlayoutparams(new relativelayout.layoutparams(relativelayout.layoutparams.match_parent, relativelayout.layoutparams.match_parent));     }      return view; } 

alayout & blayout extends relativelayout

blayout searchview , recycleview showed above.

important notice:

1) if comment out line: recyclerview.scrolltoposition(0); - no bug! (and no scroll top :) )

2) more precise conditions obtaining bug:

a) go fragment_1 track on fragment_2;

b) enter query in search (string present: recyclerview.scrolltoposition(0));

c) return fragment_1 (this time search query clean - no errors!);

d) again go fragment_2.

>>we error!

a) go fragment_1 track on fragment_2;

b) do not enter in search (string present: recyclerview.scrolltoposition (0));

c) go fragment_1. (this time search query clean - no errors!);

d) once again going fragment_2.

>>no error!