python - Is it possible to use an inline function in a Thread call? -

target callable object invoked run() method. defaults none, meaning nothing called.

i use this:

import threading  def worker():     = 3     print("bonjour {a}".format(a=a))  threading.thread(target=worker).start()

is there way chain function elements in target new 1 not need defined? (pseudocode obviously)

threading.thread(target=(a=3;print("bonjour {a}".format(a=a))).start()

i have bunch of short calls make in thread call , avoid multiplication of function definitions.

you can use lambda function in python 3.x

import threading  threading.thread(target=lambda a: print("hello, {}".format(a)), args=(["world"]))

you should take @ this question see why can't use print in python 2.x in lambda expressions.

actually, can fit many function calls lambda:

from __future__ import print_function # i'm on python 2.7 threading import thread  thread(target=(lambda: print('test') == print('hello'))).start()

that print both test , hello.

Ben