python - SyntaxError using `with open...` -

there several questions on seem deal problem. however, seem caused using pre-2.6 version of python. not case here. appreciate tracking down cause of this.

i syntax error when try use with open() f construct.

here's code (test.py):

#!/usr/bin/env python  import sys print sys.version  fname = "/tmp/test.txt"  open(fname, 'a').close()  open(fname, 'a') fh   fh.write("test") 

here's output:

$ ./test.py   file "./test.py", line 10     open(fname, 'a') fh                               ^ syntaxerror: invalid syntax 

python version being used:

$ /usr/bin/env python python 2.7.10 (default, oct 14 2015, 16:09:02) [gcc 5.2.1 20151010] on linux2 type "help", "copyright", "credits" or "license" more information. >>>  $ whereis python python: /usr/bin/python3.4 /usr/bin/python /usr/bin/python3.4m /usr/bin/python3.3 /usr/bin/python3.3m /usr/bin/python2.7 /usr/lib/python3.4 /usr/lib/python3.3 /usr/lib/python3.5 /usr/lib/python2.7 /etc/python3.4 /etc/python /etc/python3.3 /etc/python2.7 /usr/local/lib/python3.4 /usr/local/lib/python3.3 /usr/local/lib/python2.7 /usr/include/python2.7 /usr/share/python /usr/share/man/man1/python.1.gz 

my system info:

$ uname -a linux ... 4.2.0-27-generic #32-ubuntu smp fri jan 22 04:49:08 utc 2016 x86_64 x86_64 x86_64 gnu/linux 

thanks!

you need : after with statement

with open(fname, 'a') fh:   fh.write("test")