bash - why variable losing its value within the loop -


i trying use loop variable within loop. seems loosing value after using 1 time(may misunderstanding). here code

for in {2000..2014}     echo “training  representation$i_by_$i , testing representation$1999_by_$i” done

i want output should this-

training representation2000_by_2000 , testing representation1999_by_2000

but actual output this-

training representation2000 , testing representation1999_by_??

can body help?

because you're using curly quotes around string. character ” not special character shell, it's being treated part of variable name. there's no variable named i”.

change ascii double quotes around string. also, since _ can in variable name, need use ${i} when variable followed character (or other character can in variable name); otherwise, it's looking variable named $i_by_.

finally, $1999 being interpreted $1 (the first argument script)followed by999. prevent that, need escape the$`.

for in {2000..2014}     echo "training  representation${i}_by_$i , testing representation\$1999_by_$i" done

and stop using word processor edit programs. use programming editor, won't auto-correct quoting.


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