C++ Auto Generates Move Constructor With User Declared Destructor? -

according cppreference , this answer, c++ should not automatically generate move constructor if there user declared destructor. checking in practice clang, however, see auto-generated move constructor. following code prints "is_move_constructible: 1":

#include <iostream> #include <type_traits>  struct testclass {   ~testclass()   {} };  int main( int argc, char** argv ) {   std::cout << "is_move_constructible: " << std::is_move_constructible<testclass>::value << std::endl; } 

am misunderstanding "there no user-declared destructor" or std::is_move_constructible? i'm compiling '-std=c++14' , apple llvm version 7.0.2 (clang-700.1.81).

types without move constructor, copy constructor accepts const t& arguments, satisfy std::is_move_constructible , implicitly-declared copy constructor has form t::t(const t&).

if implicitly-declared copy constructor deleted, std::is_move_constructible not satisfied below.

#include <iostream> #include <type_traits>  struct testclass {   ~testclass() {}   testclass(const testclass&) = delete; };  int main( int argc, char** argv ) {   std::cout << "is_move_constructible: " << std::is_move_constructible<testclass>::value << std::endl; }