c++ - scanf problems involving string input and string comparison -

i have started working on scanf , printf in general, , in research , general screwing around have run problem in code multiple times decided make test program , have replicated error.

#include <string> #include <string.h> #include <stdio.h>  int main(){     std::string name;     std::string name2;      printf("print donald or larry: ");     scanf("%s",name);  if(strcmp(name.c_str(), "donald") == 1){     printf("you entered donald");     goto stop;   }else{     printf("you entered larry");     goto stop; }    stop: return 0; } 

when attempt compile code throws me error coming line 10

error:

error: cannot pass objects of non-trivially-copyable type 'std::string {aka class std::basic_string<char>}' through '...'| 

source:

scanf("%s", name); 

i have tried both name.c_str , &name , both don't work, name.c_str makes if statement bug out , not work &name crashes altogether, although have found &<variable> works integers far.

what doing wrong?

if trying write c++ code use following

#include <iostream> using std::cout; using std::endl; using std::cin; #include <string> using std::string;  int main(){      // declare string object     std::string name;      // output prompt , input     cout << "print donald or larry: ";     cin >> name;      if (name == "donald") {         cout << "you entered donald" << endl;     }     else if (name == "larry") {         cout << "you entered larry" << endl;     }      return 0; } 

you doing things "wrong" in code above.

1. scanf , printf c functions , should used cstrings not string objects. if using std::string, programming in c++ , should use functionality provided c++ standard library header <iostream>
2. using goto in code bad idea.