ruby - How to extract data from text columns -

i have 2 addresses side-by-side in multi-line string:

 adresse de prise en charge :                          adresse d'arrivée :     rue des capucines                                      rue des tilleuls     92210       saint cloud                                67000            strasbourg    tél.:                                                  tél.: 

i need extract addresses on left , right regexp, , assign them variables. need match:

• address1: "rue des capucines 92210 saint cloud"
• address2: "rue des tilleuls 67000 strasbourg"

i thought of separating them spaces, cant find regexp count spaces. tried:

en\s*charge\s*:\s*((.|\n)*)\s* 

and similar, gives me both addresses, , not i'm looking for. appreciated.

assuming each address section in each line indented as or further corresponding "adresse" in first line, following can extract not 2 addresses aligned sidewards, n addresses in general.

lines = string.split(/#{$/}+/) # => [ # =>   "adresse de prise en charge :                          adresse d'arrivée :", # =>   "  rue des capucines                                      rue des tilleuls", # =>   "  92210       saint cloud                                67000            strasbourg", # =>   "  tél.:                                                  tél.:" # => ]  break_points = [] lines.first.scan(/\badresse\b/){break_points.push($~.begin(0))} ranges = break_points.push(0).each_cons(2).map{|s, e| s..(e - 1)} # => [0..53, 54..-1]  address1, address2 = lines[1..-2] .map{|s| ranges.map{|r| s[r]}} .transpose .map{|a| a.join(" ").strip.squeeze(" ")} # => [ # =>   "rue des capucines 92210 saint cloud", # =>   "rue des tilleuls 67000 strasbourg" # => ]