c - How to use fgets() in 2d-arrays (multiple dimension arrays)? -

#include <stdio.h> #include <stdlib.h>  void *salloc(int x){     char **pointer;     int i;     pointer = malloc(sizeof(char)*x);     if(pointer == null){      exit(-1);     }     for(i=0; i<x; i++){         pointer[i] = malloc(sizeof(char) * 20);         if(pointer[i] == null){             exit(-1);         }     } return pointer; }  void input(int value, char **array){     for(i = 0; < value; i++){         printf("%d ----\n", i);         fgets(array[i], 20, stdin);         printf("%d ----\n", i);     } }  int main(int argc, char *argv[]){     char **array;     int value = 2;     array = salloc(value);     input(value, array);     return 0; } 

the general idea, can miss syntax. want read in string spaces. if run value 2, print:

0 ----

0 ----

1 ----

"some string"

and crashes after press enter. if value 1: crashes. if replace fgets() with:

    scanf("%s", array[i]); 

it works (except spaces).

so how fgets() work in 2d-arrays?

because work in 1d-arrays. , reason can print 1d-arrays row 2 when array has 2 rows, should able print rows 0 , 1 right?

here demonstrative program shows how fgets can used 2d array.

#include <stdio.h>  #define n   5 #define m   10  int main( void )  {     char lines[n][m];     size_t n = 0;      while( n < n && fgets( lines[n], sizeof( *lines ), stdin ) != null ) ++n;      ( size_t = 0; < n; i++ ) puts( lines[i] );      return 0; } 

if enter example

one 2 3 4 5 

then program output same

one 2 3 4 5