Displaying images retrieved from database using PHP -


i know how display image stored in database inside of particular div using php code?

the code used looks that:

<form method="post"> <input type="button" name="show" value="show"/><br/> <input type="image" id="image_show" name="img" value="img"/> </post>  if(@$_post['show'])     {         $sql="select imagedata form images order desc";         $result=mysql_query($sql) or die('invalid query'.mysql_error());         //set header         header("content-type:image/png");         echo mysql_result($result,0);         while( $row = mysql_fetch_row( $result ) )         {             echo "<img src='".$row[0]."'/>";             }         } 

but not work. how can solve task?

you need specify name of column want retrieve returned array (imagedata in case)

echo '<img src="'.$row['imagedata'].'"/>"; 

also, if dont need line if want show image , force download:

//set header header("content-type:image/png"); 

it throw error anyway printing information before form.


Comments

Popular posts from this blog

sublimetext3 - what keyboard shortcut is to comment/uncomment for this script tag in sublime -

java - No use of nillable="0" in SOAP Webservice -

ubuntu - Laravel 5.2 quickstart guide gives Not Found Error -