html - JavaScript: Pick percentage numbers -
so i'm having issue relates picking winner based on percentage.
now method pick random decimal between 1 - 0. example: [.55 or .33] , when generate number, percentage picked based on random decimal picked as.
example of this:
numbers calculated: user 1 chance> 25%. user 2 chance> 75%.
so i'm trying figure out how pick user based on decimal created.
i have javascript code here of it, don't know rest , i'm willing take possible.
<!doctype html> <html> <head> <script> function nowget(){ var picked = math.random() * (1 - 0) + 0; var numb1 = .25; var numb2 = .75; if(numb1 >= picked && picked <= numb1){ alert("25% chance wins win %: " + picked); }else if(numb2 >= picked && picked <= numb2){ alert("75% chance wins win %: " + picked); }else{ alert("nothing picked. win %: " + picked); } } </script> </head> <body> <h1>my web page</h1> <p id="demo">a paragraph</p> <button type="button" onclick="nowget()">try it</button> </body> </html>
what trying achieve getting closest number out of array of numbers. here's great answer question: https://stackoverflow.com/a/8584940/612847
adapted specific scenario, here's solution:
function closest (num, arr) { var curr = arr[0]; var diff = math.abs (num - curr); (var val = 0; val < arr.length; val++) { var newdiff = math.abs (num - arr[val]); if (newdiff < diff) { diff = newdiff; curr = arr[val]; } } return curr; } var array = [.25, .75]; var number = math.random(); var winner = closest(number, array); console.log(winner); 
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